wk+1=k1i=1∑kxi=k1(i=1∑k−1xi+xk)=k1((k−1)wk+xk)=wk−k1(wk−xk)
Model-free solution to g(w)=0:
wk+1=wk−αkg~(wk,ηk),k=1,2,3,…=wk−αk(g(wk)+ηk)
收敛条件:
- 0<c1≤∇wg(w)≤c2,∀w
- k=1∑∞αk=∞ and k=1∑∞αk2<∞
- E[ηk∣Hk]=0 and E[ηk2∣Hk]<∞,Hk={wk,wk−1,…}
wk+1=wk−αk∇wJ(wk)=wk−αkE[∇wf(wk,X)]=wk−αk∇wf(wk,xk)
收敛条件:
- 0<c1≤∇w2f(w,X)≤c2
- k=1∑∞αk=∞ and k=1∑∞αk2<∞
- {xk}k=1∞ is i.i.d.